Post/Pre increment operator question
In this article we will cover commonly asked interview question, often asked in most of the written tests- To guess the output of a program where Pre and Post increment operators are used. Post/Pre increment operator question int i = 1; i = i++; System.out.println(i); This will print 1 because i++ is post-increment and i value is still 1. int i = 1; i= --i; System.out.println(i); This will print 0 because --i is pre-increment. int i = 1; i = i++ + --i System.out.println(i); This will print 2. Now most of the people will mark 3 as an answer but there is a logic behind its output. Explanation: i++ evaluates to 1. It will increment the value of i by 1 before --i is evaluated. The equation will be 1 + (2-1) = 1 + 1 = 2.