Bold Technology | Noida| Automation testing Interview | SDET

In this article, we will share Interview testing experience with Bold Technologies in Noida for SDET/ automation testing role.

Bold Technology

Company - Bold Technology

Location - Noida

Job role - SDET/ Automation testing 

Mode of Interview - Google Meet

Interviewer - Anurima Chatterjee

• Tell me about yourself?
• Describe your framework?
• Then she asked to share screen and open any IDE/ online compiler
• Write a Java program for below I/O
•  my name is Rohan
•  ym eman si nahoR
• Write a program to print 2nd highest value from an array?
• Write Sql query to print count of employees which are repeated multiple times?

Solutions - We practiced this program at Java online compiler. Would request to practice it before looking at solution

Program for below I/O

I/p - my name is Rohan

O/p - ym eman si nahoR

class HelloWorld {

    public static void main(String[] args) {

 

 String str = "my name is Rohan";

 String rev = "";

 

 String arr[] =str.split(" ");

 

 for(int i = 0; i< arr.length; i++ ){ // length is used for Array

        // rev = rev + str.charAt(i);  

        String word = arr[i];      // 4 words stored in array - my, name, is, Rohan

        String rev_word = "";

        for(int j = word.length() - 1; j>=0; j--) // Not the difference, length() is used for string

        {

            

            rev_word = rev_word + word.charAt(j);

        }

        rev = rev + rev_word + " ";

        

        }

        System.out.println(str);

        System.out.println(rev);

 }

}

Program to print 2nd highest number in an array

I/P - 1, 8 ,15, 6

O/p - 8

Solution - 

class HelloWorld {

    public static void main(String[] args) {

        

        int a[] = {100,253,55,79};

        int temp;

        int size;

        size = a.length;

    

    for(int i = 0;i<size; i++) 

    {

        for(int j = i+1; j<size; j++)

        {

            if(a[i] > a[j])

            {

                temp = a[i];

                a[i] = a[j];

                a[j] = temp;

            }

        }

    }

    System.out.print(a[size-2]);

        

}

}

Solution 3 - Sql query to find count of repeated employees

select name from EMP

group by name

having count(name) > 1;